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-125+15x+8x^2=0
a = 8; b = 15; c = -125;
Δ = b2-4ac
Δ = 152-4·8·(-125)
Δ = 4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4225}=65$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-65}{2*8}=\frac{-80}{16} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+65}{2*8}=\frac{50}{16} =3+1/8 $
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